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1344034414101 = 3448011471367
BaseRepresentation
bin10011100011101110101…
…100011001111000010101
311202111012001212110110010
4103203232230121320111
5134010040302222401
62505235121550433
7166050266010411
oct23435654317025
94674161773403
101344034414101
1147900242a265
121985964a5419
1399984c5a582
14490a18a7d41
1524e64bcded6
hex138eeb19e15

1344034414101 has 4 divisors (see below), whose sum is σ = 1792045885472. Its totient is φ = 896022942732.

The previous prime is 1344034414081. The next prime is 1344034414123. The reversal of 1344034414101 is 1014144304431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1344034414101 - 25 = 1344034414069 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1344034414901) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224005735681 + ... + 224005735686.

It is an arithmetic number, because the mean of its divisors is an integer number (448011471368).

Almost surely, 21344034414101 is an apocalyptic number.

It is an amenable number.

1344034414101 is a deficient number, since it is larger than the sum of its proper divisors (448011471371).

1344034414101 is an equidigital number, since it uses as much as digits as its factorization.

1344034414101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 448011471370.

The product of its (nonzero) digits is 9216, while the sum is 30.

Adding to 1344034414101 its reverse (1014144304431), we get a palindrome (2358178718532).

The spelling of 1344034414101 in words is "one trillion, three hundred forty-four billion, thirty-four million, four hundred fourteen thousand, one hundred one".

Divisors: 1 3 448011471367 1344034414101