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13440401322 = 239497235871
BaseRepresentation
bin11001000010001110…
…00011111110101010
31021200200111010111120
430201013003332222
5210011220320242
610101402240110
7654031345335
oct144107037652
937620433446
1013440401322
115777835497
1227311b6036
1313626ba6ba
1491704961c
15539e461ec
hex3211c3faa

13440401322 has 16 divisors (see below), whose sum is σ = 26883747072. Its totient is φ = 4479643040.

The previous prime is 13440401309. The next prime is 13440401327. The reversal of 13440401322 is 22310404431.

13440401322 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 13440401292 and 13440401301.

It is not an unprimeable number, because it can be changed into a prime (13440401327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60954 + ... + 174917.

It is an arithmetic number, because the mean of its divisors is an integer number (1680234192).

Almost surely, 213440401322 is an apocalyptic number.

13440401322 is an abundant number, since it is smaller than the sum of its proper divisors (13443345750).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13440401322 is a wasteful number, since it uses less digits than its factorization.

13440401322 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 245373.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 13440401322 its reverse (22310404431), we get a palindrome (35750805753).

The spelling of 13440401322 in words is "thirteen billion, four hundred forty million, four hundred one thousand, three hundred twenty-two".

Divisors: 1 2 3 6 9497 18994 28491 56982 235871 471742 707613 1415226 2240066887 4480133774 6720200661 13440401322