Base | Representation |
---|---|
bin | 11001000010001111… |
… | …01000011001011101 |
3 | 1021200200202201010102 |
4 | 30201013220121131 |
5 | 210011240103433 |
6 | 10101405350445 |
7 | 654032536256 |
oct | 144107503135 |
9 | 37620681112 |
10 | 13440550493 |
11 | 5777927577 |
12 | 2731268425 |
13 | 1362740576 |
14 | 917087b2d |
15 | 539e754e8 |
hex | 3211e865d |
13440550493 has 4 divisors (see below), whose sum is σ = 13448361948. Its totient is φ = 13432739040.
The previous prime is 13440550481. The next prime is 13440550499. The reversal of 13440550493 is 39405504431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 39405504431 = 1861 ⋅21174371.
It can be written as a sum of positive squares in 2 ways, for example, as 9375467929 + 4065082564 = 96827^2 + 63758^2 .
It is a cyclic number.
It is not a de Polignac number, because 13440550493 - 212 = 13440546397 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13440550499) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3903146 + ... + 3906587.
It is an arithmetic number, because the mean of its divisors is an integer number (3362090487).
Almost surely, 213440550493 is an apocalyptic number.
It is an amenable number.
13440550493 is a deficient number, since it is larger than the sum of its proper divisors (7811455).
13440550493 is an equidigital number, since it uses as much as digits as its factorization.
13440550493 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7811454.
The product of its (nonzero) digits is 129600, while the sum is 38.
The spelling of 13440550493 in words is "thirteen billion, four hundred forty million, five hundred fifty thousand, four hundred ninety-three".
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