1344102037 has 4 divisors (see below), whose sum is σ = 1402541280. Its totient is φ = 1285662796.

The previous prime is 1344102029. The next prime is 1344102073. The reversal of 1344102037 is 7302014431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1344102037 - 2³ = 1344102029 is a prime.

It is a super-2 number, since 2×1344102037² = 3613220571735098738, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1344103037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29219587 + ... + 29219632.

It is an arithmetic number, because the mean of its divisors is an integer number (350635320).

Almost surely, 2^1344102037 is an apocalyptic number.

It is an amenable number.

1344102037 is a deficient number, since it is larger than the sum of its proper divisors (58439243).

1344102037 is an equidigital number, since it uses as much as digits as its factorization.

1344102037 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58439242.

The product of its (nonzero) digits is 2016, while the sum is 25.

The square root of 1344102037 is about 36661.9971769133. The cubic root of 1344102037 is about 1103.5975976578.

Adding to 1344102037 its reverse (7302014431), we get a palindrome (8646116468).

The spelling of 1344102037 in words is "one billion, three hundred forty-four million, one hundred two thousand, thirty-seven".