Base | Representation |
---|---|
bin | 1100001110010111101111… |
… | …1001010111010000010110 |
3 | 1202120221122120201010012011 |
4 | 3003211323321113100112 |
5 | 3230204213003213324 |
6 | 44330420300014434 |
7 | 2555040200004133 |
oct | 303457371272026 |
9 | 52527576633164 |
10 | 13441031304214 |
11 | 4312344845268 |
12 | 1610b6623141a |
13 | 766639c26997 |
14 | 34679973158a |
15 | 18497337dc94 |
hex | c397be57416 |
13441031304214 has 4 divisors (see below), whose sum is σ = 20161546956324. Its totient is φ = 6720515652106.
The previous prime is 13441031304203. The next prime is 13441031304241. The reversal of 13441031304214 is 41240313014431.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×134410313042142 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3360257826052 + ... + 3360257826055.
It is an arithmetic number, because the mean of its divisors is an integer number (5040386739081).
Almost surely, 213441031304214 is an apocalyptic number.
13441031304214 is a deficient number, since it is larger than the sum of its proper divisors (6720515652110).
13441031304214 is an equidigital number, since it uses as much as digits as its factorization.
13441031304214 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6720515652109.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 13441031304214 its reverse (41240313014431), we get a palindrome (54681344318645).
The spelling of 13441031304214 in words is "thirteen trillion, four hundred forty-one billion, thirty-one million, three hundred four thousand, two hundred fourteen".
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