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13441120356721 is a prime number
BaseRepresentation
bin1100001110011000000100…
…1101000100100101110001
31202120221212210021110021011
43003212001031010211301
53230204403302403341
644330433200430521
72555042330642341
oct303460115044561
952527783243234
1013441120356721
114312390039782
121610b90018441
13766652506585
143467a74b2d21
1518497b0beb81
hexc3981344971

13441120356721 has 2 divisors, whose sum is σ = 13441120356722. Its totient is φ = 13441120356720.

The previous prime is 13441120356701. The next prime is 13441120356901. The reversal of 13441120356721 is 12765302114431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8595222561121 + 4845897795600 = 2931761^2 + 2201340^2 .

It is an emirp because it is prime and its reverse (12765302114431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13441120356721 is a prime.

It is not a weakly prime, because it can be changed into another prime (13441120356701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720560178360 + 6720560178361.

It is an arithmetic number, because the mean of its divisors is an integer number (6720560178361).

Almost surely, 213441120356721 is an apocalyptic number.

It is an amenable number.

13441120356721 is a deficient number, since it is larger than the sum of its proper divisors (1).

13441120356721 is an equidigital number, since it uses as much as digits as its factorization.

13441120356721 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120960, while the sum is 40.

The spelling of 13441120356721 in words is "thirteen trillion, four hundred forty-one billion, one hundred twenty million, three hundred fifty-six thousand, seven hundred twenty-one".