Base | Representation |
---|---|
bin | 10011100011110011011… |
… | …100111110010100111011 |
3 | 11202111101122002210210111 |
4 | 103203303130332110323 |
5 | 134010221222131123 |
6 | 2505251053125151 |
7 | 166052255442241 |
oct | 23436334762473 |
9 | 4674348083714 |
10 | 1344114255163 |
11 | 479043502009 |
12 | 1985b91897b7 |
13 | 999986634c4 |
14 | 490ac32c791 |
15 | 24e6bc0090d |
hex | 138f373e53b |
1344114255163 has 2 divisors, whose sum is σ = 1344114255164. Its totient is φ = 1344114255162.
The previous prime is 1344114255103. The next prime is 1344114255167. The reversal of 1344114255163 is 3615524114431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1344114255163 - 237 = 1206675301691 is a prime.
It is not a weakly prime, because it can be changed into another prime (1344114255167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672057127581 + 672057127582.
It is an arithmetic number, because the mean of its divisors is an integer number (672057127582).
Almost surely, 21344114255163 is an apocalyptic number.
1344114255163 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344114255163 is an equidigital number, since it uses as much as digits as its factorization.
1344114255163 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 172800, while the sum is 40.
Adding to 1344114255163 its reverse (3615524114431), we get a palindrome (4959638369594).
The spelling of 1344114255163 in words is "one trillion, three hundred forty-four billion, one hundred fourteen million, two hundred fifty-five thousand, one hundred sixty-three".
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