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134412323113 is a prime number
BaseRepresentation
bin111110100101110011…
…0010100100100101001
3110211221102111111001101
41331023212110210221
54200234023314423
6141425334321401
712465601616065
oct1751346244451
9424842444041
10134412323113
1152005285862
12220724b9261
13c8a1060903
1467114b0aa5
15376a3d37ad
hex1f4b994929

134412323113 has 2 divisors, whose sum is σ = 134412323114. Its totient is φ = 134412323112.

The previous prime is 134412323099. The next prime is 134412323119. The reversal of 134412323113 is 311323214431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113453101584 + 20959221529 = 336828^2 + 144773^2 .

It is a cyclic number.

It is not a de Polignac number, because 134412323113 - 29 = 134412322601 is a prime.

It is not a weakly prime, because it can be changed into another prime (134412323119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67206161556 + 67206161557.

It is an arithmetic number, because the mean of its divisors is an integer number (67206161557).

Almost surely, 2134412323113 is an apocalyptic number.

It is an amenable number.

134412323113 is a deficient number, since it is larger than the sum of its proper divisors (1).

134412323113 is an equidigital number, since it uses as much as digits as its factorization.

134412323113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5184, while the sum is 28.

Adding to 134412323113 its reverse (311323214431), we get a palindrome (445735537544).

The spelling of 134412323113 in words is "one hundred thirty-four billion, four hundred twelve million, three hundred twenty-three thousand, one hundred thirteen".