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1344125542 = 2672062771
BaseRepresentation
bin101000000011101…
…1011101001100110
310110200012122121111
41100013123221212
510223044004132
6341213135234
745210610234
oct12007335146
93420178544
101344125542
1162a7a6461
1231618a51a
13185617576
14ca729954
157d009647
hex501dba66

1344125542 has 4 divisors (see below), whose sum is σ = 2016188316. Its totient is φ = 672062770.

The previous prime is 1344125521. The next prime is 1344125557. The reversal of 1344125542 is 2455214431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 2455214431 = 8927586679.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 336031384 + ... + 336031387.

It is an arithmetic number, because the mean of its divisors is an integer number (504047079).

Almost surely, 21344125542 is an apocalyptic number.

1344125542 is a deficient number, since it is larger than the sum of its proper divisors (672062774).

1344125542 is an equidigital number, since it uses as much as digits as its factorization.

1344125542 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 672062773.

The product of its digits is 19200, while the sum is 31.

The square root of 1344125542 is about 36662.3177390628. The cubic root of 1344125542 is about 1103.6040306789.

Adding to 1344125542 its reverse (2455214431), we get a palindrome (3799339973).

Subtracting 1344125542 from its reverse (2455214431), we obtain a square (1111088889 = 333332).

It can be divided in two parts, 13441 and 25542, that added together give a palindrome (38983).

The spelling of 1344125542 in words is "one billion, three hundred forty-four million, one hundred twenty-five thousand, five hundred forty-two".

Divisors: 1 2 672062771 1344125542