13441325103421 has 4 divisors (see below), whose sum is σ = 13449902849152. Its totient is φ = 13432747357692.

The previous prime is 13441325103361. The next prime is 13441325103433. The reversal of 13441325103421 is 12430152314431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13441325103421 - 2¹⁵ = 13441325070653 is a prime.

It is a super-4 number, since 4×13441325103421⁴ (a number of 54 digits) contains 4444 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13441325103491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4288870515 + ... + 4288873648.

It is an arithmetic number, because the mean of its divisors is an integer number (3362475712288).

Almost surely, 2^{13441325103421} is an apocalyptic number.

It is an amenable number.

13441325103421 is a deficient number, since it is larger than the sum of its proper divisors (8577745731).

13441325103421 is an equidigital number, since it uses as much as digits as its factorization.

13441325103421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8577745730.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 13441325103421 its reverse (12430152314431), we get a palindrome (25871477417852).

The spelling of 13441325103421 in words is "thirteen trillion, four hundred forty-one billion, three hundred twenty-five million, one hundred three thousand, four hundred twenty-one".