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13441405051552 = 25420043907861
BaseRepresentation
bin1100001110011001001000…
…1011000110001010100000
31202120222121121222110011011
43003212102023012022200
53230210444143122202
644330521330430304
72555052355545412
oct303462213061240
952528547873134
1013441405051552
11431251680a165
12161104b432394
137666994a5b5a
143467d32209b2
151849960a8bd7
hexc39922c62a0

13441405051552 has 12 divisors (see below), whose sum is σ = 26462766195306. Its totient is φ = 6720702525760.

The previous prime is 13441405051523. The next prime is 13441405051567. The reversal of 13441405051552 is 25515050414431.

It can be written as a sum of positive squares in only one way, i.e., 11724351239056 + 1717053812496 = 3424084^2 + 1310364^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 210021953899 + ... + 210021953962.

Almost surely, 213441405051552 is an apocalyptic number.

It is an amenable number.

13441405051552 is a deficient number, since it is larger than the sum of its proper divisors (13021361143754).

13441405051552 is an equidigital number, since it uses as much as digits as its factorization.

13441405051552 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 420043907871 (or 420043907863 counting only the distinct ones).

The product of its (nonzero) digits is 240000, while the sum is 40.

Adding to 13441405051552 its reverse (25515050414431), we get a palindrome (38956455465983).

The spelling of 13441405051552 in words is "thirteen trillion, four hundred forty-one billion, four hundred five million, fifty-one thousand, five hundred fifty-two".

Divisors: 1 2 4 8 16 32 420043907861 840087815722 1680175631444 3360351262888 6720702525776 13441405051552