Base | Representation |
---|---|
bin | 1100001110011001001000… |
… | …1101000000001110100011 |
3 | 1202120222121122220211222121 |
4 | 3003212102031000032203 |
5 | 3230210444310122043 |
6 | 44330521345245111 |
7 | 2555052363030145 |
oct | 303462215001643 |
9 | 52528548824877 |
10 | 13441405551523 |
11 | 4312517020864 |
12 | 161104b633797 |
13 | 76669961c5b1 |
14 | 3467d3310c95 |
15 | 184996156ded |
hex | c39923403a3 |
13441405551523 has 2 divisors, whose sum is σ = 13441405551524. Its totient is φ = 13441405551522.
The previous prime is 13441405551433. The next prime is 13441405551527. The reversal of 13441405551523 is 32515550414431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13441405551523 - 213 = 13441405543331 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13441405551523.
It is not a weakly prime, because it can be changed into another prime (13441405551527) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720702775761 + 6720702775762.
It is an arithmetic number, because the mean of its divisors is an integer number (6720702775762).
Almost surely, 213441405551523 is an apocalyptic number.
13441405551523 is a deficient number, since it is larger than the sum of its proper divisors (1).
13441405551523 is an equidigital number, since it uses as much as digits as its factorization.
13441405551523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720000, while the sum is 43.
Adding to 13441405551523 its reverse (32515550414431), we get a palindrome (45956955965954).
The spelling of 13441405551523 in words is "thirteen trillion, four hundred forty-one billion, four hundred five million, five hundred fifty-one thousand, five hundred twenty-three".
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