1344141130341 has 4 divisors (see below), whose sum is σ = 1792188173792. Its totient is φ = 896094086892.

The previous prime is 1344141130337. The next prime is 1344141130391. The reversal of 1344141130341 is 1430311414431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1344141130341 - 2² = 1344141130337 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1344141130299 and 1344141130308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1344141130391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224023521721 + ... + 224023521726.

It is an arithmetic number, because the mean of its divisors is an integer number (448047043448).

Almost surely, 2^{1344141130341} is an apocalyptic number.

It is an amenable number.

1344141130341 is a deficient number, since it is larger than the sum of its proper divisors (448047043451).

1344141130341 is an equidigital number, since it uses as much as digits as its factorization.

1344141130341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 448047043450.

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 1344141130341 its reverse (1430311414431), we get a palindrome (2774452544772).

The spelling of 1344141130341 in words is "one trillion, three hundred forty-four billion, one hundred forty-one million, one hundred thirty thousand, three hundred forty-one".