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134415718271953 is a prime number
BaseRepresentation
bin11110100100000000011001…
…001000111100101111010001
3122121221000110111222022021021
4132210000121020330233101
5120104231342334200303
61153513421205155441
740212133542550426
oct3644003110745721
9577830414868237
10134415718271953
1139913427832598
12130aa8000bbb81
135a0046a2a4091
142529a81057d4d
1510816dbd42ebd
hex7a401923cbd1

134415718271953 has 2 divisors, whose sum is σ = 134415718271954. Its totient is φ = 134415718271952.

The previous prime is 134415718271929. The next prime is 134415718272001. The reversal of 134415718271953 is 359172817514431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 69340794260544 + 65074924011409 = 8327112^2 + 8066903^2 .

It is a cyclic number.

It is not a de Polignac number, because 134415718271953 - 25 = 134415718271921 is a prime.

It is a super-3 number, since 3×1344157182719533 (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134415718271891 and 134415718271900.

It is not a weakly prime, because it can be changed into another prime (134415718271353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67207859135976 + 67207859135977.

It is an arithmetic number, because the mean of its divisors is an integer number (67207859135977).

Almost surely, 2134415718271953 is an apocalyptic number.

It is an amenable number.

134415718271953 is a deficient number, since it is larger than the sum of its proper divisors (1).

134415718271953 is an equidigital number, since it uses as much as digits as its factorization.

134415718271953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 25401600, while the sum is 61.

The spelling of 134415718271953 in words is "one hundred thirty-four trillion, four hundred fifteen billion, seven hundred eighteen million, two hundred seventy-one thousand, nine hundred fifty-three".