134422004323 has 4 divisors (see below), whose sum is σ = 135807798280. Its totient is φ = 133036210368.

The previous prime is 134422004303. The next prime is 134422004329. The reversal of 134422004323 is 323400224431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 323400224431 = 53 ⋅6101891027.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134422004323 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134422004291 and 134422004300.

It is not an unprimeable number, because it can be changed into a prime (134422004329) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 692896833 + ... + 692897026.

It is an arithmetic number, because the mean of its divisors is an integer number (33951949570).

Almost surely, 2^134422004323 is an apocalyptic number.

134422004323 is a deficient number, since it is larger than the sum of its proper divisors (1385793957).

134422004323 is an equidigital number, since it uses as much as digits as its factorization.

134422004323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1385793956.

The product of its (nonzero) digits is 13824, while the sum is 28.

Adding to 134422004323 its reverse (323400224431), we get a palindrome (457822228754).

The spelling of 134422004323 in words is "one hundred thirty-four billion, four hundred twenty-two million, four thousand, three hundred twenty-three".