Base | Representation |
---|---|
bin | 11001000010011110… |
… | …10001100111011011 |
3 | 1021200211112111212122 |
4 | 30201033101213123 |
5 | 210012243214311 |
6 | 10101520331455 |
7 | 654055553333 |
oct | 144117214733 |
9 | 37624474778 |
10 | 13442554331 |
11 | 5778a76038 |
12 | 2731a73b8b |
13 | 1362c9267b |
14 | 91744a0c3 |
15 | 53a21e0db |
hex | 3213d19db |
13442554331 has 2 divisors, whose sum is σ = 13442554332. Its totient is φ = 13442554330.
The previous prime is 13442554289. The next prime is 13442554403. The reversal of 13442554331 is 13345524431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13442554331 - 210 = 13442553307 is a prime.
It is a super-2 number, since 2×134425543312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13442554291 and 13442554300.
It is not a weakly prime, because it can be changed into another prime (13442554031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721277165 + 6721277166.
It is an arithmetic number, because the mean of its divisors is an integer number (6721277166).
Almost surely, 213442554331 is an apocalyptic number.
13442554331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13442554331 is an equidigital number, since it uses as much as digits as its factorization.
13442554331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 86400, while the sum is 35.
The spelling of 13442554331 in words is "thirteen billion, four hundred forty-two million, five hundred fifty-four thousand, three hundred thirty-one".
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