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1344300342841 is a prime number
BaseRepresentation
bin10011100011111110100…
…010110101111000111001
311202111212121021001002201
4103203332202311320321
5134011111341432331
62505321341430201
7166060005244021
oct23437642657071
94674777231081
101344300342841
11479129552485
1219864b56b361
13999c8089261
14490c8d2ca81
1524e7d20ca61
hex138fe8b5e39

1344300342841 has 2 divisors, whose sum is σ = 1344300342842. Its totient is φ = 1344300342840.

The previous prime is 1344300342829. The next prime is 1344300342857. The reversal of 1344300342841 is 1482430034431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 750352680441 + 593947662400 = 866229^2 + 770680^2 .

It is an emirp because it is prime and its reverse (1482430034431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1344300342841 - 231 = 1342152859193 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1344300342841.

It is not a weakly prime, because it can be changed into another prime (1344300345841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672150171420 + 672150171421.

It is an arithmetic number, because the mean of its divisors is an integer number (672150171421).

Almost surely, 21344300342841 is an apocalyptic number.

It is an amenable number.

1344300342841 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344300342841 is an equidigital number, since it uses as much as digits as its factorization.

1344300342841 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 110592, while the sum is 37.

The spelling of 1344300342841 in words is "one trillion, three hundred forty-four billion, three hundred million, three hundred forty-two thousand, eight hundred forty-one".