Base | Representation |
---|---|
bin | 11001000010100010… |
… | …00101110011010111 |
3 | 1021200212102200200120 |
4 | 30201101011303113 |
5 | 210012403431411 |
6 | 10101534443023 |
7 | 654062604651 |
oct | 144121056327 |
9 | 37625380616 |
10 | 13443030231 |
11 | 5779270644 |
12 | 2732063473 |
13 | 13630cb177 |
14 | 9175316d1 |
15 | 53a2b5106 |
hex | 321445cd7 |
13443030231 has 4 divisors (see below), whose sum is σ = 17924040312. Its totient is φ = 8962020152.
The previous prime is 13443030199. The next prime is 13443030241. The reversal of 13443030231 is 13203034431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13443030231 - 25 = 13443030199 is a prime.
It is a super-2 number, since 2×134430302312 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13443030241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2240505036 + ... + 2240505041.
It is an arithmetic number, because the mean of its divisors is an integer number (4481010078).
Almost surely, 213443030231 is an apocalyptic number.
13443030231 is a deficient number, since it is larger than the sum of its proper divisors (4481010081).
13443030231 is an equidigital number, since it uses as much as digits as its factorization.
13443030231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4481010080.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 13443030231 its reverse (13203034431), we get a palindrome (26646064662).
The spelling of 13443030231 in words is "thirteen billion, four hundred forty-three million, thirty thousand, two hundred thirty-one".
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