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134430520001 is a prime number
BaseRepresentation
bin111110100110010101…
…1101111001011000001
3110211222200201222111012
41331030223233023001
54200303203120001
6141431224330305
712466212365201
oct1751453571301
9424880658435
10134430520001
1152014584408
1222078613995
13c8a4a623bb
146713a8a401
15376bcca2bb
hex1f4caef2c1

134430520001 has 2 divisors, whose sum is σ = 134430520002. Its totient is φ = 134430520000.

The previous prime is 134430519983. The next prime is 134430520031. The reversal of 134430520001 is 100025034431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131783520400 + 2646999601 = 363020^2 + 51449^2 .

It is a cyclic number.

It is not a de Polignac number, because 134430520001 - 214 = 134430503617 is a prime.

It is a super-2 number, since 2×1344305200012 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (134430520031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67215260000 + 67215260001.

It is an arithmetic number, because the mean of its divisors is an integer number (67215260001).

Almost surely, 2134430520001 is an apocalyptic number.

It is an amenable number.

134430520001 is a deficient number, since it is larger than the sum of its proper divisors (1).

134430520001 is an equidigital number, since it uses as much as digits as its factorization.

134430520001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 134430520001 its reverse (100025034431), we get a palindrome (234455554432).

The spelling of 134430520001 in words is "one hundred thirty-four billion, four hundred thirty million, five hundred twenty thousand, one".