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134431414232034 = 23110320312997013
BaseRepresentation
bin11110100100001111000000…
…101100010010001111100010
3122121222111222101200200201010
4132210033000230102033202
5120110011014020411114
61153524534504121350
740213230523164123
oct3644170054221742
9577874871620633
10134431414232034
113991a051794727
12130b1860766256
135a01a9c07671a
14252a72d88404a
151081d09cccc59
hex7a43c0b123e2

134431414232034 has 16 divisors (see below), whose sum is σ = 269106584441472. Its totient is φ = 44769845414448.

The previous prime is 134431414232009. The next prime is 134431414232041. The reversal of 134431414232034 is 430232414134431.

It is a junction number, because it is equal to n+sod(n) for n = 134431414231983 and 134431414232001.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10156491889 + ... + 10156505124.

It is an arithmetic number, because the mean of its divisors is an integer number (16819161527592).

Almost surely, 2134431414232034 is an apocalyptic number.

134431414232034 is an abundant number, since it is smaller than the sum of its proper divisors (134675170209438).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134431414232034 is a wasteful number, since it uses less digits than its factorization.

134431414232034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20312998121.

The product of its (nonzero) digits is 331776, while the sum is 39.

Adding to 134431414232034 its reverse (430232414134431), we get a palindrome (564663828366465).

The spelling of 134431414232034 in words is "one hundred thirty-four trillion, four hundred thirty-one billion, four hundred fourteen million, two hundred thirty-two thousand, thirty-four".

Divisors: 1 2 3 6 1103 2206 3309 6618 20312997013 40625994026 60938991039 121877982078 22405235705339 44810471410678 67215707116017 134431414232034