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13443244200134 = 273130975217051
BaseRepresentation
bin1100001110011111111111…
…0010111001000011000110
31202121011100210122212201022
43003213333302321003012
53230223231003401014
644331424030031142
72555146060213550
oct303477762710306
952534323585638
1013443244200134
11431327a982771
1216114833484b2
13766900522058
143469295a84d0
15184a52796a8e
hexc39ffcb90c6

13443244200134 has 16 divisors (see below), whose sum is σ = 23788966695936. Its totient is φ = 5575539069000.

The previous prime is 13443244200119. The next prime is 13443244200241. The reversal of 13443244200134 is 43100244234431.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13443244200094 and 13443244200103.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15487608092 + ... + 15487608959.

It is an arithmetic number, because the mean of its divisors is an integer number (1486810418496).

Almost surely, 213443244200134 is an apocalyptic number.

13443244200134 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

13443244200134 is a deficient number, since it is larger than the sum of its proper divisors (10345722495802).

13443244200134 is a wasteful number, since it uses less digits than its factorization.

13443244200134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30975217091.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 13443244200134 its reverse (43100244234431), we get a palindrome (56543488434565).

The spelling of 13443244200134 in words is "thirteen trillion, four hundred forty-three billion, two hundred forty-four million, two hundred thousand, one hundred thirty-four".

Divisors: 1 2 7 14 31 62 217 434 30975217051 61950434102 216826519357 433653038714 960231728581 1920463457162 6721622100067 13443244200134