Base | Representation |
---|---|
bin | 11110100100010000011111… |
… | …010010101101101001110011 |
3 | 122121222200002000011100120121 |
4 | 132210100133102231221303 |
5 | 120110022241322122313 |
6 | 1153525400201551111 |
7 | 40213315044451222 |
oct | 3644203722555163 |
9 | 577880060140517 |
10 | 134433001364083 |
11 | 3991a796677504 |
12 | 130b20241a5497 |
13 | 5a01c92b25406 |
14 | 252a840588cb9 |
15 | 1081d9e2d928d |
hex | 7a441f4ada73 |
134433001364083 has 2 divisors, whose sum is σ = 134433001364084. Its totient is φ = 134433001364082.
The previous prime is 134433001364021. The next prime is 134433001364161. The reversal of 134433001364083 is 380463100334431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134433001364083 - 233 = 134424411429491 is a prime.
It is not a weakly prime, because it can be changed into another prime (134433001364003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67216500682041 + 67216500682042.
It is an arithmetic number, because the mean of its divisors is an integer number (67216500682042).
Almost surely, 2134433001364083 is an apocalyptic number.
134433001364083 is a deficient number, since it is larger than the sum of its proper divisors (1).
134433001364083 is an equidigital number, since it uses as much as digits as its factorization.
134433001364083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 746496, while the sum is 43.
The spelling of 134433001364083 in words is "one hundred thirty-four trillion, four hundred thirty-three billion, one million, three hundred sixty-four thousand, eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •