13443302113 has 4 divisors (see below), whose sum is σ = 13456094128. Its totient is φ = 13430510100.

The previous prime is 13443302063. The next prime is 13443302149. The reversal of 13443302113 is 31120334431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31120334431 = 89 ⋅349666679.

It is a cyclic number.

It is not a de Polignac number, because 13443302113 - 2⁹ = 13443301601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13443302153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6394431 + ... + 6396532.

It is an arithmetic number, because the mean of its divisors is an integer number (3364023532).

Almost surely, 2^13443302113 is an apocalyptic number.

It is an amenable number.

13443302113 is a deficient number, since it is larger than the sum of its proper divisors (12792015).

13443302113 is a wasteful number, since it uses less digits than its factorization.

13443302113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12792014.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13443302113 its reverse (31120334431), we get a palindrome (44563636544).

The spelling of 13443302113 in words is "thirteen billion, four hundred forty-three million, three hundred two thousand, one hundred thirteen".