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13443302149 is a prime number
BaseRepresentation
bin11001000010100100…
…01000001100000101
31021200212221111200121
430201102020030011
5210012441132044
610101544341541
7654065116504
oct144122101405
937625844617
1013443302149
115779436972
1227321748b1
131363194b74
149175a283b
1553a31a984
hex321488305

13443302149 has 2 divisors, whose sum is σ = 13443302150. Its totient is φ = 13443302148.

The previous prime is 13443302063. The next prime is 13443302153. The reversal of 13443302149 is 94120334431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12333213025 + 1110089124 = 111055^2 + 33318^2 .

It is an emirp because it is prime and its reverse (94120334431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13443302149 - 219 = 13442777861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13443302189) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721651074 + 6721651075.

It is an arithmetic number, because the mean of its divisors is an integer number (6721651075).

Almost surely, 213443302149 is an apocalyptic number.

It is an amenable number.

13443302149 is a deficient number, since it is larger than the sum of its proper divisors (1).

13443302149 is an equidigital number, since it uses as much as digits as its factorization.

13443302149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 34.

The spelling of 13443302149 in words is "thirteen billion, four hundred forty-three million, three hundred two thousand, one hundred forty-nine".