Base | Representation |
---|---|
bin | 111110100110011110… |
… | …1001110010100110011 |
3 | 110212000000100212121211 |
4 | 1331030331032110303 |
5 | 4200310341312201 |
6 | 141431510500551 |
7 | 12466266346603 |
oct | 1751475162463 |
9 | 425000325554 |
10 | 134435104051 |
11 | 52017125486 |
12 | 2207a064757 |
13 | c8a59a8a61 |
14 | 6714520c03 |
15 | 376c3d3651 |
hex | 1f4cf4e533 |
134435104051 has 2 divisors, whose sum is σ = 134435104052. Its totient is φ = 134435104050.
The previous prime is 134435104033. The next prime is 134435104073. The reversal of 134435104051 is 150401534431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134435104051 - 227 = 134300886323 is a prime.
It is a super-2 number, since 2×1344351040512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134435104031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67217552025 + 67217552026.
It is an arithmetic number, because the mean of its divisors is an integer number (67217552026).
Almost surely, 2134435104051 is an apocalyptic number.
134435104051 is a deficient number, since it is larger than the sum of its proper divisors (1).
134435104051 is an equidigital number, since it uses as much as digits as its factorization.
134435104051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 134435104051 its reverse (150401534431), we get a palindrome (284836638482).
The spelling of 134435104051 in words is "one hundred thirty-four billion, four hundred thirty-five million, one hundred four thousand, fifty-one".
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