1344354113 has 4 divisors (see below), whose sum is σ = 1372957440. Its totient is φ = 1315750788.

The previous prime is 1344354103. The next prime is 1344354119. The reversal of 1344354113 is 3114534431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3114534431 = 29 ⋅107397739.

It is a cyclic number.

It is not a de Polignac number, because 1344354113 - 2⁶ = 1344354049 is a prime.

It is a super-2 number, since 2×1344354113² = 3614575962280033538, which contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1344354119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14301593 + ... + 14301686.

It is an arithmetic number, because the mean of its divisors is an integer number (343239360).

Almost surely, 2^1344354113 is an apocalyptic number.

It is an amenable number.

1344354113 is a deficient number, since it is larger than the sum of its proper divisors (28603327).

1344354113 is an equidigital number, since it uses as much as digits as its factorization.

1344354113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28603326.

The product of its digits is 8640, while the sum is 29.

The square root of 1344354113 is about 36665.4348535511. The cubic root of 1344354113 is about 1103.6665837594. Note that the first 3 decimals are identical.

Adding to 1344354113 its reverse (3114534431), we get a palindrome (4458888544).

The spelling of 1344354113 in words is "one billion, three hundred forty-four million, three hundred fifty-four thousand, one hundred thirteen".