Base | Representation |
---|---|
bin | 10011100100000101111… |
… | …011010100100001101110 |
3 | 11202112012020022122121002 |
4 | 103210011323110201232 |
5 | 134011340043402202 |
6 | 2505341524240302 |
7 | 166063041102341 |
oct | 23440573244156 |
9 | 4675166278532 |
10 | 1344424200302 |
11 | 479192459417 |
12 | 198684b40092 |
13 | 99a17933bb1 |
14 | 490db570458 |
15 | 24e89026302 |
hex | 13905ed486e |
1344424200302 has 4 divisors (see below), whose sum is σ = 2016636300456. Its totient is φ = 672212100150.
The previous prime is 1344424200283. The next prime is 1344424200331. The reversal of 1344424200302 is 2030024244431.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 336106050074 + ... + 336106050077.
It is an arithmetic number, because the mean of its divisors is an integer number (504159075114).
Almost surely, 21344424200302 is an apocalyptic number.
1344424200302 is a deficient number, since it is larger than the sum of its proper divisors (672212100154).
1344424200302 is an equidigital number, since it uses as much as digits as its factorization.
1344424200302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 672212100153.
The product of its (nonzero) digits is 18432, while the sum is 29.
Adding to 1344424200302 its reverse (2030024244431), we get a palindrome (3374448444733).
The spelling of 1344424200302 in words is "one trillion, three hundred forty-four billion, four hundred twenty-four million, two hundred thousand, three hundred two".
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