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13444353504331 is a prime number
BaseRepresentation
bin1100001110100100000111…
…1010100011010001001011
31202121021020010000100222221
43003221001322203101023
53230233013444114311
644332130054154511
72555215420150561
oct303510172432113
952537203010887
1013444353504331
11431379a0723a2
121611732952a37
13766a492ac979
143469d2a49a31
15184ab9d69671
hexc3a41ea344b

13444353504331 has 2 divisors, whose sum is σ = 13444353504332. Its totient is φ = 13444353504330.

The previous prime is 13444353504317. The next prime is 13444353504371. The reversal of 13444353504331 is 13340535344431.

It is a weak prime.

It is an emirp because it is prime and its reverse (13340535344431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13444353504331 is a prime.

It is a super-2 number, since 2×134443535043312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13444353504371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6722176752165 + 6722176752166.

It is an arithmetic number, because the mean of its divisors is an integer number (6722176752166).

Almost surely, 213444353504331 is an apocalyptic number.

13444353504331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13444353504331 is an equidigital number, since it uses as much as digits as its factorization.

13444353504331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1555200, while the sum is 43.

Adding to 13444353504331 its reverse (13340535344431), we get a palindrome (26784888848762).

The spelling of 13444353504331 in words is "thirteen trillion, four hundred forty-four billion, three hundred fifty-three million, five hundred four thousand, three hundred thirty-one".