Base | Representation |
---|---|
bin | 11001000010101100… |
… | …11001001011100001 |
3 | 1021200222001022112101 |
4 | 30201112121023201 |
5 | 210013232422241 |
6 | 10102024330401 |
7 | 654110454463 |
oct | 144126311341 |
9 | 37628038471 |
10 | 13444420321 |
11 | 577a02aa82 |
12 | 2732613a01 |
13 | 1363496ac7 |
14 | 9177b4133 |
15 | 53a48be31 |
hex | 3215992e1 |
13444420321 has 2 divisors, whose sum is σ = 13444420322. Its totient is φ = 13444420320.
The previous prime is 13444420309. The next prime is 13444420357. The reversal of 13444420321 is 12302444431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9927930321 + 3516490000 = 99639^2 + 59300^2 .
It is an emirp because it is prime and its reverse (12302444431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13444420321 - 25 = 13444420289 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13444420321.
It is not a weakly prime, because it can be changed into another prime (13444420361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6722210160 + 6722210161.
It is an arithmetic number, because the mean of its divisors is an integer number (6722210161).
Almost surely, 213444420321 is an apocalyptic number.
It is an amenable number.
13444420321 is a deficient number, since it is larger than the sum of its proper divisors (1).
13444420321 is an equidigital number, since it uses as much as digits as its factorization.
13444420321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 13444420321 its reverse (12302444431), we get a palindrome (25746864752).
The spelling of 13444420321 in words is "thirteen billion, four hundred forty-four million, four hundred twenty thousand, three hundred twenty-one".
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