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134446852577273 is a prime number
BaseRepresentation
bin11110100100011101011000…
…111000111001011111111001
3122122000222211022122220000112
4132210131120320321133321
5120110234123224433043
61153540010441314105
740214315225022035
oct3644353070713771
9578028738586015
10134446852577273
1139925654291a35
12130b484aa95935
135a0338c66b652
14252b395db11c5
15108241032c518
hex7a4758e397f9

134446852577273 has 2 divisors, whose sum is σ = 134446852577274. Its totient is φ = 134446852577272.

The previous prime is 134446852577239. The next prime is 134446852577287. The reversal of 134446852577273 is 372775258644431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89141393526784 + 45305459050489 = 9441472^2 + 6730933^2 .

It is a cyclic number.

It is not a de Polignac number, because 134446852577273 - 26 = 134446852577209 is a prime.

It is a super-2 number, since 2×1344468525772732 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (134446852577203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67223426288636 + 67223426288637.

It is an arithmetic number, because the mean of its divisors is an integer number (67223426288637).

Almost surely, 2134446852577273 is an apocalyptic number.

It is an amenable number.

134446852577273 is a deficient number, since it is larger than the sum of its proper divisors (1).

134446852577273 is an equidigital number, since it uses as much as digits as its factorization.

134446852577273 is an evil number, because the sum of its binary digits is even.

The product of its digits is 948326400, while the sum is 68.

The spelling of 134446852577273 in words is "one hundred thirty-four trillion, four hundred forty-six billion, eight hundred fifty-two million, five hundred seventy-seven thousand, two hundred seventy-three".