Base | Representation |
---|---|
bin | 111110100111100001… |
… | …1100100111101011001 |
3 | 110212002110122020101111 |
4 | 1331033003210331121 |
5 | 4200343400332212 |
6 | 141435205420321 |
7 | 12500204616046 |
oct | 1751703447531 |
9 | 425073566344 |
10 | 134470324057 |
11 | 52034aa0823 |
12 | 22089a0a6a1 |
13 | c8b008a9b4 |
14 | 671908c1cd |
15 | 377053dea7 |
hex | 1f4f0e4f59 |
134470324057 has 2 divisors, whose sum is σ = 134470324058. Its totient is φ = 134470324056.
The previous prime is 134470324049. The next prime is 134470324061. The reversal of 134470324057 is 750423074431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 124070199696 + 10400124361 = 352236^2 + 101981^2 .
It is a cyclic number.
It is not a de Polignac number, because 134470324057 - 23 = 134470324049 is a prime.
It is a super-3 number, since 3×1344703240573 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (134470024057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67235162028 + 67235162029.
It is an arithmetic number, because the mean of its divisors is an integer number (67235162029).
Almost surely, 2134470324057 is an apocalyptic number.
It is an amenable number.
134470324057 is a deficient number, since it is larger than the sum of its proper divisors (1).
134470324057 is an equidigital number, since it uses as much as digits as its factorization.
134470324057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 282240, while the sum is 40.
Adding to 134470324057 its reverse (750423074431), we get a palindrome (884893398488).
The spelling of 134470324057 in words is "one hundred thirty-four billion, four hundred seventy million, three hundred twenty-four thousand, fifty-seven".
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