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134486113 is a prime number
BaseRepresentation
bin10000000010000…
…01100001100001
3100101001121021011
420001001201201
5233412023423
621202300521
73222053536
oct1001014141
9311047234
10134486113
1169a06453
1239057741
1321b296a8
1413c0ad8d
15bc17b0d
hex8041861

134486113 has 2 divisors, whose sum is σ = 134486114. Its totient is φ = 134486112.

The previous prime is 134486089. The next prime is 134486117. The reversal of 134486113 is 311684431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133818624 + 667489 = 11568^2 + 817^2 .

It is a cyclic number.

It is not a de Polignac number, because 134486113 - 25 = 134486081 is a prime.

It is not a weakly prime, because it can be changed into another prime (134486117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67243056 + 67243057.

It is an arithmetic number, because the mean of its divisors is an integer number (67243057).

Almost surely, 2134486113 is an apocalyptic number.

It is an amenable number.

134486113 is a deficient number, since it is larger than the sum of its proper divisors (1).

134486113 is an equidigital number, since it uses as much as digits as its factorization.

134486113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 31.

The square root of 134486113 is about 11596.8147782053. The cubic root of 134486113 is about 512.3410419576.

The spelling of 134486113 in words is "one hundred thirty-four million, four hundred eighty-six thousand, one hundred thirteen".