Base | Representation |
---|---|
bin | 10011100100100100101… |
… | …111100111100101100111 |
3 | 11202120112021012021222201 |
4 | 103210210233213211213 |
5 | 134013414423220333 |
6 | 2505505114035331 |
7 | 166111616541031 |
oct | 23444457474547 |
9 | 4676467167881 |
10 | 1344941226343 |
11 | 479428294770 |
12 | 1987aa118b47 |
13 | 99a9aa9a870 |
14 | 4914a0b8c51 |
15 | 24eb960417d |
hex | 13924be7967 |
1344941226343 has 32 divisors (see below), whose sum is σ = 1634970173760. Its totient is φ = 1089427906560.
The previous prime is 1344941226337. The next prime is 1344941226353. The reversal of 1344941226343 is 3436221494431.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1344941226343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1344941226293 and 1344941226302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1344941226323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 17200071 + ... + 17278087.
It is an arithmetic number, because the mean of its divisors is an integer number (51092817930).
Almost surely, 21344941226343 is an apocalyptic number.
1344941226343 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1344941226343 is a deficient number, since it is larger than the sum of its proper divisors (290028947417).
1344941226343 is a wasteful number, since it uses less digits than its factorization.
1344941226343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 82227.
The product of its digits is 1492992, while the sum is 46.
The spelling of 1344941226343 in words is "one trillion, three hundred forty-four billion, nine hundred forty-one million, two hundred twenty-six thousand, three hundred forty-three".
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