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13450088856343 = 43312792764101
BaseRepresentation
bin1100001110111001011111…
…0001001011101100010111
31202121211000211002102212211
43003232113301023230113
53230331240221400333
644334515134454251
72555510511635506
oct303562761135427
952554024072784
1013450088856343
114316172575237
121612873664387
137674515a7999
14346db864883d
15184d03627ecd
hexc3b97c4bb17

13450088856343 has 4 divisors (see below), whose sum is σ = 13762881620488. Its totient is φ = 13137296092200.

The previous prime is 13450088856313. The next prime is 13450088856409. The reversal of 13450088856343 is 34365888005431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13450088856343 - 213 = 13450088848151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13450088856313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156396382008 + ... + 156396382093.

It is an arithmetic number, because the mean of its divisors is an integer number (3440720405122).

Almost surely, 213450088856343 is an apocalyptic number.

13450088856343 is a deficient number, since it is larger than the sum of its proper divisors (312792764145).

13450088856343 is an equidigital number, since it uses as much as digits as its factorization.

13450088856343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 312792764144.

The product of its (nonzero) digits is 33177600, while the sum is 58.

The spelling of 13450088856343 in words is "thirteen trillion, four hundred fifty billion, eighty-eight million, eight hundred fifty-six thousand, three hundred forty-three".

Divisors: 1 43 312792764101 13450088856343