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134503156553 is a prime number
BaseRepresentation
bin111110101000100000…
…0110100101101001001
3110212011202102022002212
41331101000310231021
54200430302002203
6141442341234505
712501053652443
oct1752100645511
9425152368085
10134503156553
1152051586317
1222098a02a35
13c8b6b14ccc
14671d597493
1537733771d8
hex1f51034b49

134503156553 has 2 divisors, whose sum is σ = 134503156554. Its totient is φ = 134503156552.

The previous prime is 134503156547. The next prime is 134503156631. The reversal of 134503156553 is 355651305431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81597636409 + 52905520144 = 285653^2 + 230012^2 .

It is a cyclic number.

It is not a de Polignac number, because 134503156553 - 226 = 134436047689 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134503156553.

It is not a weakly prime, because it can be changed into another prime (134503126553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67251578276 + 67251578277.

It is an arithmetic number, because the mean of its divisors is an integer number (67251578277).

Almost surely, 2134503156553 is an apocalyptic number.

It is an amenable number.

134503156553 is a deficient number, since it is larger than the sum of its proper divisors (1).

134503156553 is an equidigital number, since it uses as much as digits as its factorization.

134503156553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 405000, while the sum is 41.

The spelling of 134503156553 in words is "one hundred thirty-four billion, five hundred three million, one hundred fifty-six thousand, five hundred fifty-three".