Base | Representation |
---|---|
bin | 10011100100101010010… |
… | …011010011111010000001 |
3 | 11202120202202122111212012 |
4 | 103210222103103322001 |
5 | 134014112311001433 |
6 | 2505522244342305 |
7 | 166114131230345 |
oct | 23445223237201 |
9 | 4676682574765 |
10 | 1345034468993 |
11 | 479475990306 |
12 | 1988153a4995 |
13 | 99ab41b6727 |
14 | 4915862b625 |
15 | 24ec28c1848 |
hex | 1392a4d3e81 |
1345034468993 has 2 divisors, whose sum is σ = 1345034468994. Its totient is φ = 1345034468992.
The previous prime is 1345034468917. The next prime is 1345034469001. The reversal of 1345034468993 is 3998644305431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1110867516529 + 234166952464 = 1053977^2 + 483908^2 .
It is an emirp because it is prime and its reverse (3998644305431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1345034468993 - 210 = 1345034467969 is a prime.
It is not a weakly prime, because it can be changed into another prime (1345034468893) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672517234496 + 672517234497.
It is an arithmetic number, because the mean of its divisors is an integer number (672517234497).
Almost surely, 21345034468993 is an apocalyptic number.
It is an amenable number.
1345034468993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1345034468993 is an equidigital number, since it uses as much as digits as its factorization.
1345034468993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 33592320, while the sum is 59.
The spelling of 1345034468993 in words is "one trillion, three hundred forty-five billion, thirty-four million, four hundred sixty-eight thousand, nine hundred ninety-three".
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