Base | Representation |
---|---|
bin | 111110101000100010… |
… | …1110001011110011001 |
3 | 110212011211212012220222 |
4 | 1331101011301132121 |
5 | 4200431120012131 |
6 | 141442425125425 |
7 | 12501100665266 |
oct | 1752105613631 |
9 | 425154765828 |
10 | 134504454041 |
11 | 52052292121 |
12 | 22099329875 |
13 | c8b717a759 |
14 | 671d81426d |
15 | 377353187b |
hex | 1f51171799 |
134504454041 has 2 divisors, whose sum is σ = 134504454042. Its totient is φ = 134504454040.
The previous prime is 134504454013. The next prime is 134504454047. The reversal of 134504454041 is 140454405431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 126164198416 + 8340255625 = 355196^2 + 91325^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134504454041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134504453992 and 134504454010.
It is not a weakly prime, because it can be changed into another prime (134504454047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67252227020 + 67252227021.
It is an arithmetic number, because the mean of its divisors is an integer number (67252227021).
Almost surely, 2134504454041 is an apocalyptic number.
It is an amenable number.
134504454041 is a deficient number, since it is larger than the sum of its proper divisors (1).
134504454041 is an equidigital number, since it uses as much as digits as its factorization.
134504454041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 76800, while the sum is 35.
Adding to 134504454041 its reverse (140454405431), we get a palindrome (274958859472).
The spelling of 134504454041 in words is "one hundred thirty-four billion, five hundred four million, four hundred fifty-four thousand, forty-one".
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