Base | Representation |
---|---|
bin | 11001000011011111… |
… | …00101101001111011 |
3 | 1021201102110212110211 |
4 | 30201233211221323 |
5 | 210021430300034 |
6 | 10102422051551 |
7 | 654220553245 |
oct | 144157455173 |
9 | 37642425424 |
10 | 13451025019 |
11 | 5782831203 |
12 | 2734879bb7 |
13 | 136496a103 |
14 | 918613095 |
15 | 53ad43d64 |
hex | 321be5a7b |
13451025019 has 2 divisors, whose sum is σ = 13451025020. Its totient is φ = 13451025018.
The previous prime is 13451024999. The next prime is 13451025097. The reversal of 13451025019 is 91052015431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13451025019 - 213 = 13451016827 is a prime.
It is a super-2 number, since 2×134510250192 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13451025619) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6725512509 + 6725512510.
It is an arithmetic number, because the mean of its divisors is an integer number (6725512510).
Almost surely, 213451025019 is an apocalyptic number.
13451025019 is a deficient number, since it is larger than the sum of its proper divisors (1).
13451025019 is an equidigital number, since it uses as much as digits as its factorization.
13451025019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 31.
The spelling of 13451025019 in words is "thirteen billion, four hundred fifty-one million, twenty-five thousand, nineteen".
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