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1345113003403 = 132326916723813
BaseRepresentation
bin10011100100101110111…
…110111001010110001011
311202120222020102110211001
4103210232332321112023
5134014242412102103
62505534131515431
7166116103610551
oct23445676712613
94676866373731
101345113003403
11479506250384
12198837758b77
1399ac75529b0
1449164c31bd1
1524ec973601d
hex1392efb958b

1345113003403 has 16 divisors (see below), whose sum is σ = 1517184406080. Its totient is φ = 1183243146624.

The previous prime is 1345113003391. The next prime is 1345113003407. The reversal of 1345113003403 is 3043003115431.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1345113003403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1345113003407) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8281476 + ... + 8442337.

It is an arithmetic number, because the mean of its divisors is an integer number (94824025380).

Almost surely, 21345113003403 is an apocalyptic number.

1345113003403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1345113003403 is a deficient number, since it is larger than the sum of its proper divisors (172071402677).

1345113003403 is a wasteful number, since it uses less digits than its factorization.

1345113003403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16724118.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 1345113003403 its reverse (3043003115431), we get a palindrome (4388116118834).

The spelling of 1345113003403 in words is "one trillion, three hundred forty-five billion, one hundred thirteen million, three thousand, four hundred three".

Divisors: 1 13 23 269 299 3497 6187 80431 16723813 217409569 384647699 4498705697 5000420087 58483174061 103470231031 1345113003403