Base | Representation |
---|---|
bin | 10011100100101110111… |
… | …110111001010110001011 |
3 | 11202120222020102110211001 |
4 | 103210232332321112023 |
5 | 134014242412102103 |
6 | 2505534131515431 |
7 | 166116103610551 |
oct | 23445676712613 |
9 | 4676866373731 |
10 | 1345113003403 |
11 | 479506250384 |
12 | 198837758b77 |
13 | 99ac75529b0 |
14 | 49164c31bd1 |
15 | 24ec973601d |
hex | 1392efb958b |
1345113003403 has 16 divisors (see below), whose sum is σ = 1517184406080. Its totient is φ = 1183243146624.
The previous prime is 1345113003391. The next prime is 1345113003407. The reversal of 1345113003403 is 3043003115431.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1345113003403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1345113003407) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8281476 + ... + 8442337.
It is an arithmetic number, because the mean of its divisors is an integer number (94824025380).
Almost surely, 21345113003403 is an apocalyptic number.
1345113003403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1345113003403 is a deficient number, since it is larger than the sum of its proper divisors (172071402677).
1345113003403 is a wasteful number, since it uses less digits than its factorization.
1345113003403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16724118.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 1345113003403 its reverse (3043003115431), we get a palindrome (4388116118834).
The spelling of 1345113003403 in words is "one trillion, three hundred forty-five billion, one hundred thirteen million, three thousand, four hundred three".
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