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1345132124302 = 2672566062151
BaseRepresentation
bin10011100100110000000…
…111110101100010001110
311202121000120101220202111
4103210300013311202032
5134014312310434202
62505540053414234
7166116425255611
oct23446007654216
94677016356674
101345132124302
1147951602017a
1219884203a37a
1399acb4b8c35
14491675ac178
1524ecb2616d7
hex139301f588e

1345132124302 has 4 divisors (see below), whose sum is σ = 2017698186456. Its totient is φ = 672566062150.

The previous prime is 1345132124279. The next prime is 1345132124311. The reversal of 1345132124302 is 2034212315431.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×13451321243022 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 336283031074 + ... + 336283031077.

It is an arithmetic number, because the mean of its divisors is an integer number (504424546614).

Almost surely, 21345132124302 is an apocalyptic number.

1345132124302 is a deficient number, since it is larger than the sum of its proper divisors (672566062154).

1345132124302 is an equidigital number, since it uses as much as digits as its factorization.

1345132124302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 672566062153.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 1345132124302 its reverse (2034212315431), we get a palindrome (3379344439733).

The spelling of 1345132124302 in words is "one trillion, three hundred forty-five billion, one hundred thirty-two million, one hundred twenty-four thousand, three hundred two".

Divisors: 1 2 672566062151 1345132124302