Base | Representation |
---|---|
bin | 10011100100110000110… |
… | …010111110101110000010 |
3 | 11202121001100200111220102 |
4 | 103210300302332232002 |
5 | 134014323204342424 |
6 | 2505541140042402 |
7 | 166116623352044 |
oct | 23446062765602 |
9 | 4677040614812 |
10 | 1345143434114 |
11 | 479521445427 |
12 | 198845993402 |
13 | 99b00948a2c |
14 | 49168cb3a94 |
15 | 24ecc2477ae |
hex | 13930cbeb82 |
1345143434114 has 4 divisors (see below), whose sum is σ = 2017715151174. Its totient is φ = 672571717056.
The previous prime is 1345143434077. The next prime is 1345143434143. The reversal of 1345143434114 is 4114343415431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1276979101225 + 68164332889 = 1130035^2 + 261083^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 336285858527 + ... + 336285858530.
Almost surely, 21345143434114 is an apocalyptic number.
1345143434114 is a deficient number, since it is larger than the sum of its proper divisors (672571717060).
1345143434114 is an equidigital number, since it uses as much as digits as its factorization.
1345143434114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 672571717059.
The product of its digits is 138240, while the sum is 38.
Adding to 1345143434114 its reverse (4114343415431), we get a palindrome (5459486849545).
The spelling of 1345143434114 in words is "one trillion, three hundred forty-five billion, one hundred forty-three million, four hundred thirty-four thousand, one hundred fourteen".
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