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1345236429409 is a prime number
BaseRepresentation
bin10011100100110110010…
…101101110101001100001
311202121021211200011110121
4103210312111232221201
5134020021011220114
62505554301200241
7166122132661255
oct23446625565141
94677254604417
101345236429409
11479569992144
12198870b60081
1399b16ca9132
14491773a0265
1524ed54b6a24
hex1393656ea61

1345236429409 has 2 divisors, whose sum is σ = 1345236429410. Its totient is φ = 1345236429408.

The previous prime is 1345236429367. The next prime is 1345236429473. The reversal of 1345236429409 is 9049246325431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 888206347809 + 457030081600 = 942447^2 + 676040^2 .

It is a cyclic number.

It is not a de Polignac number, because 1345236429409 - 211 = 1345236427361 is a prime.

It is a super-2 number, since 2×13452364294092 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1345236429209) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672618214704 + 672618214705.

It is an arithmetic number, because the mean of its divisors is an integer number (672618214705).

Almost surely, 21345236429409 is an apocalyptic number.

It is an amenable number.

1345236429409 is a deficient number, since it is larger than the sum of its proper divisors (1).

1345236429409 is an equidigital number, since it uses as much as digits as its factorization.

1345236429409 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5598720, while the sum is 52.

The spelling of 1345236429409 in words is "one trillion, three hundred forty-five billion, two hundred thirty-six million, four hundred twenty-nine thousand, four hundred nine".