Base | Representation |
---|---|
bin | 10011100100110110110… |
… | …100100011110001101101 |
3 | 11202121022101212202210102 |
4 | 103210312310203301231 |
5 | 134020030043330331 |
6 | 2505555150320445 |
7 | 166122261451613 |
oct | 23446664436155 |
9 | 4677271782712 |
10 | 1345244511341 |
11 | 479573502225 |
12 | 1988737b9125 |
13 | 99b18878943 |
14 | 491784a56b3 |
15 | 24ed60614cb |
hex | 13936d23c6d |
1345244511341 has 8 divisors (see below), whose sum is σ = 1360399536000. Its totient is φ = 1330090373920.
The previous prime is 1345244511329. The next prime is 1345244511361. The reversal of 1345244511341 is 1431154425431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1345244511341 - 26 = 1345244511277 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1345244511295 and 1345244511304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1345244511361) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3107546 + ... + 3513876.
It is an arithmetic number, because the mean of its divisors is an integer number (170049942000).
Almost surely, 21345244511341 is an apocalyptic number.
It is an amenable number.
1345244511341 is a deficient number, since it is larger than the sum of its proper divisors (15155024659).
1345244511341 is an equidigital number, since it uses as much as digits as its factorization.
1345244511341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 443619.
The product of its digits is 115200, while the sum is 38.
Adding to 1345244511341 its reverse (1431154425431), we get a palindrome (2776398936772).
The spelling of 1345244511341 in words is "one trillion, three hundred forty-five billion, two hundred forty-four million, five hundred eleven thousand, three hundred forty-one".
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