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1345253465301 = 3448417821767
BaseRepresentation
bin10011100100110111010…
…110101101110011010101
311202121100000201200022120
4103210313112231303111
5134020034341342201
62510000110250153
7166122430533504
oct23446726556325
94677300650276
101345253465301
11479578568499
121988767b6959
1399b1a692345
144917975683b
1524ed6c2e536
hex139375adcd5

1345253465301 has 4 divisors (see below), whose sum is σ = 1793671287072. Its totient is φ = 896835643532.

The previous prime is 1345253465249. The next prime is 1345253465333. The reversal of 1345253465301 is 1035643525431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1345253465301 - 218 = 1345253203157 is a prime.

It is a super-2 number, since 2×13452534653012 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1345253465401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224208910881 + ... + 224208910886.

It is an arithmetic number, because the mean of its divisors is an integer number (448417821768).

Almost surely, 21345253465301 is an apocalyptic number.

It is an amenable number.

1345253465301 is a deficient number, since it is larger than the sum of its proper divisors (448417821771).

1345253465301 is an equidigital number, since it uses as much as digits as its factorization.

1345253465301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 448417821770.

The product of its (nonzero) digits is 648000, while the sum is 42.

The spelling of 1345253465301 in words is "one trillion, three hundred forty-five billion, two hundred fifty-three million, four hundred sixty-five thousand, three hundred one".

Divisors: 1 3 448417821767 1345253465301