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1345255221433 is a prime number
BaseRepresentation
bin10011100100110111011…
…101011010100010111001
311202121100011000220021111
4103210313131122202321
5134020040314041213
62510000212040321
7166122451466434
oct23446735324271
94677304026244
101345255221433
11479579557942
121988773030a1
1399b1ab58786
1449179a9281b
1524ed6e79a3d
hex1393775a8b9

1345255221433 has 2 divisors, whose sum is σ = 1345255221434. Its totient is φ = 1345255221432.

The previous prime is 1345255221379. The next prime is 1345255221437. The reversal of 1345255221433 is 3341225525431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1344876257344 + 378964089 = 1159688^2 + 19467^2 .

It is a cyclic number.

It is not a de Polignac number, because 1345255221433 - 29 = 1345255220921 is a prime.

It is a super-2 number, since 2×13452552214332 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1345255221437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672627610716 + 672627610717.

It is an arithmetic number, because the mean of its divisors is an integer number (672627610717).

Almost surely, 21345255221433 is an apocalyptic number.

It is an amenable number.

1345255221433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1345255221433 is an equidigital number, since it uses as much as digits as its factorization.

1345255221433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 432000, while the sum is 40.

The spelling of 1345255221433 in words is "one trillion, three hundred forty-five billion, two hundred fifty-five million, two hundred twenty-one thousand, four hundred thirty-three".