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13453525441 is a prime number
BaseRepresentation
bin11001000011110010…
…01000000111000001
31021201121011220102001
430201321020013001
5210023100303231
610102551424001
7654251036146
oct144171100701
937647156361
1013453525441
115784189874
122735685001
131365334255
14918aa43cd
1553b189b61
hex321e481c1

13453525441 has 2 divisors, whose sum is σ = 13453525442. Its totient is φ = 13453525440.

The previous prime is 13453525409. The next prime is 13453525469. The reversal of 13453525441 is 14452535431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8468600625 + 4984924816 = 92025^2 + 70604^2 .

It is a cyclic number.

It is not a de Polignac number, because 13453525441 - 25 = 13453525409 is a prime.

It is a super-4 number, since 4×134535254414 (a number of 42 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13453525441.

It is not a weakly prime, because it can be changed into another prime (13453525471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6726762720 + 6726762721.

It is an arithmetic number, because the mean of its divisors is an integer number (6726762721).

Almost surely, 213453525441 is an apocalyptic number.

It is an amenable number.

13453525441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13453525441 is an equidigital number, since it uses as much as digits as its factorization.

13453525441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 144000, while the sum is 37.

The spelling of 13453525441 in words is "thirteen billion, four hundred fifty-three million, five hundred twenty-five thousand, four hundred forty-one".