Base | Representation |
---|---|
bin | 111110101001110101… |
… | …1000001101011010001 |
3 | 110212021212101002221212 |
4 | 1331103223001223101 |
5 | 4201023212233121 |
6 | 141451013425505 |
7 | 12502135132103 |
oct | 1752353015321 |
9 | 425255332855 |
10 | 134547774161 |
11 | 52074790179 |
12 | 220ab93b295 |
13 | c8c3137568 |
14 | 672548d573 |
15 | 377723c25b |
hex | 1f53ac1ad1 |
134547774161 has 2 divisors, whose sum is σ = 134547774162. Its totient is φ = 134547774160.
The previous prime is 134547774157. The next prime is 134547774169. The reversal of 134547774161 is 161477745431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 99331498561 + 35216275600 = 315169^2 + 187660^2 .
It is an emirp because it is prime and its reverse (161477745431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134547774161 - 22 = 134547774157 is a prime.
It is not a weakly prime, because it can be changed into another prime (134547774169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67273887080 + 67273887081.
It is an arithmetic number, because the mean of its divisors is an integer number (67273887081).
Almost surely, 2134547774161 is an apocalyptic number.
It is an amenable number.
134547774161 is a deficient number, since it is larger than the sum of its proper divisors (1).
134547774161 is an equidigital number, since it uses as much as digits as its factorization.
134547774161 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1975680, while the sum is 50.
The spelling of 134547774161 in words is "one hundred thirty-four billion, five hundred forty-seven million, seven hundred seventy-four thousand, one hundred sixty-one".
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