Base | Representation |
---|---|
bin | 10011100101000110001… |
… | …101001000111010001111 |
3 | 11202121222101112200220010 |
4 | 103211012031020322033 |
5 | 134021042132110020 |
6 | 2510040530324303 |
7 | 166131544336152 |
oct | 23450615107217 |
9 | 4677871480803 |
10 | 1345502613135 |
11 | 47969616999a |
12 | 198926129693 |
13 | 99b5a196bb5 |
14 | 491a088dc99 |
15 | 24eeda45de0 |
hex | 13946348e8f |
1345502613135 has 16 divisors (see below), whose sum is σ = 2202869395584. Its totient is φ = 700912988832.
The previous prime is 1345502612977. The next prime is 1345502613181. The reversal of 1345502613135 is 5313162055431.
It is not a de Polignac number, because 1345502613135 - 226 = 1345435504271 is a prime.
It is a super-2 number, since 2×13455026131352 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1345502613093 and 1345502613102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1043024637 + ... + 1043025926.
It is an arithmetic number, because the mean of its divisors is an integer number (137679337224).
Almost surely, 21345502613135 is an apocalyptic number.
1345502613135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1345502613135 is a deficient number, since it is larger than the sum of its proper divisors (857366782449).
1345502613135 is a wasteful number, since it uses less digits than its factorization.
1345502613135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2086050614.
The product of its (nonzero) digits is 162000, while the sum is 39.
Adding to 1345502613135 its reverse (5313162055431), we get a palindrome (6658664668566).
The spelling of 1345502613135 in words is "one trillion, three hundred forty-five billion, five hundred two million, six hundred thirteen thousand, one hundred thirty-five".
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