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134551134503 = 532538700651
BaseRepresentation
bin111110101001111011…
…1110110000100100111
3110212022002200211110222
41331103313312010213
54201030042301003
6141451213434555
712502205526032
oct1752367660447
9425262624428
10134551134503
1152076675915
12220b0a9ba5b
13c8c3a42c26
146725ac6019
1537776a2c38
hex1f53df6127

134551134503 has 4 divisors (see below), whose sum is σ = 137089835208. Its totient is φ = 132012433800.

The previous prime is 134551134481. The next prime is 134551134517. The reversal of 134551134503 is 305431155431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134551134503 - 212 = 134551130407 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134551134803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1269350273 + ... + 1269350378.

It is an arithmetic number, because the mean of its divisors is an integer number (34272458802).

Almost surely, 2134551134503 is an apocalyptic number.

134551134503 is a deficient number, since it is larger than the sum of its proper divisors (2538700705).

134551134503 is an equidigital number, since it uses as much as digits as its factorization.

134551134503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2538700704.

The product of its (nonzero) digits is 54000, while the sum is 35.

Adding to 134551134503 its reverse (305431155431), we get a palindrome (439982289934).

The spelling of 134551134503 in words is "one hundred thirty-four billion, five hundred fifty-one million, one hundred thirty-four thousand, five hundred three".

Divisors: 1 53 2538700651 134551134503