Base | Representation |
---|---|
bin | 111110101001111100… |
… | …1010110111000111011 |
3 | 110212022010102222110112 |
4 | 1331103321112320323 |
5 | 4201030142443232 |
6 | 141451230134535 |
7 | 12502212100142 |
oct | 1752371267073 |
9 | 425263388415 |
10 | 134551531067 |
11 | 52076916858 |
12 | 220b105144b |
13 | c8c3b51595 |
14 | 6725b8a759 |
15 | 37777304b2 |
hex | 1f53e56e3b |
134551531067 has 2 divisors, whose sum is σ = 134551531068. Its totient is φ = 134551531066.
The previous prime is 134551531021. The next prime is 134551531109. The reversal of 134551531067 is 760135155431.
It is a strong prime.
It is an emirp because it is prime and its reverse (760135155431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134551531067 - 26 = 134551531003 is a prime.
It is a super-2 number, since 2×1345515310672 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134551531007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67275765533 + 67275765534.
It is an arithmetic number, because the mean of its divisors is an integer number (67275765534).
Almost surely, 2134551531067 is an apocalyptic number.
134551531067 is a deficient number, since it is larger than the sum of its proper divisors (1).
134551531067 is an equidigital number, since it uses as much as digits as its factorization.
134551531067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 189000, while the sum is 41.
Adding to 134551531067 its reverse (760135155431), we get a palindrome (894686686498).
The spelling of 134551531067 in words is "one hundred thirty-four billion, five hundred fifty-one million, five hundred thirty-one thousand, sixty-seven".
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